
How do you find the slope of a line parallel to 6x-7y=10? - Socratic
Aug 26, 2016 · Parallel lines have equal slope. The slope of line 6x −7y = 10 or 7y = 6x − 10 or y = 6 7 x − 10 7 ∴ slope = 6 7. Hence the slope of the line is also 6 7 [Ans]
How do you factor #6x^2+x-1# - Socratic
Jan 29, 2017 · 6x^2+x-1 = (2x+1) (3x-1) Here are a couple of methods (in no particular order): Method 1 Note that: (ax+1) (bx-1) = abx^2+ (b-a)x-1 Comparing with: 6x^2+x-1 we want to find a, b such that …
How do you simplify -6x + 7 (4 - 3x)? - Socratic
Jun 4, 2018 · First of all, get rid of the parenthesis, multpilying each term inside it by 7: 7(4 −3x) = 7 ⋅ 4 − 7 ⋅ 3x = 28 − 21x The expression is now −6x + 28 −21x Now sum the similar terms, i.e. those …
What are the real zeros of this function #f (x)=3x^3+6x^2 ... - Socratic
f (x) has zeros +-sqrt (5) and -2 Given: f (x) = 3x^3+6x^2-15x-30 Note that all of the terms are divisible by 3. In addition, the ratio of the first and second terms is the same as that of the third and fourth terms.
How do you solve the quadratic equation by completing the square: …
Aug 1, 2015 · Explanation: In order to solve this quadratic equation by completing the square, you need to write the left side of the equation as the square of a binomial.
How you find (f/g) (x) and (f/g) when f (x)=6x^2−22x+12 ... - Socratic
#= (6x^2-22x+12)/ (x-3)# #"factorise the numerator"# #"take out a "color (blue)"common factor "2# #=2 (3x^2-11x+6)# #"factor the quadratic using the a-c method"# #"the factors of the product "3xx6=18# …
How do you solve 3 ( 9- 6x ) = - 153? | Socratic
Sep 9, 2017 · First, divide each side of the equation by 3 to eliminate the need for parenthesis while keeping the equation balanced: 3(9 −6x) 3 = − 153 3 3(9 − 6x) 3 = −51 9 − 6x = −51 Next, subtract 9 …
How do you find the vertex of # f (x)= -3x^2-6x-7#? - Socratic
Explanation: As you are using # f (x) # I am assuming you are at a higher level of Mathematics.
If f (x) = 6x—3, what is the value of f (1)+f (2)? | Socratic
Nov 11, 2015 · f (1) + f (2) = 12. To get to this answer we have to substitute x in f (x)by 1 and then by 2. How? Let's see: f (x) = 6x - 3. So, f (1) = 6 (1) - 3 = 6 - 3 = 3, f (1 ...
How do you divide # (12x^4-18x^3+36x^2)-:6x^3#? - Socratic
We're dividing a single term, #6x^3#, into a polynomial, so we can take advantage of the following fact which allows us to effectively divide one term into other terms: